10.0 m of wire consists of 5.3 mof copper followed by 4.7 m ofaluminum of equal

Question

10.0 m of wire consists of 5.3 mof copper followed by 4.7 m ofaluminum of equal diameter (both 1.0 mm). A voltage difference of68 V is placed across the compositewire. (a) What is the total resistance of the wire?
(b) What is the current flow through the wire?
(c) What is the voltage across the aluminum part?
(d)What is the voltage across the copper part? 10.0 m of wire consists of 5.3 mof copper followed by 4.7 m ofaluminum of equal diameter (both 1.0 mm). A voltage difference of68 V is placed across the compositewire. (a) What is the total resistance of the wire?
(b) What is the current flow through the wire?
(c) What is the voltage across the aluminum part?
(d)What is the voltage across the copper part?

Explanation / Answer

length of copper wire = 5.3m aluminium wire = 4.7 m diamter of wire = 1mm = 1*10-3m, r = (1/2*10-3) voltage difference = v = 68v resistance ofcopper wire = R1= A/L but (cooper) =1.7*10-8 m plug values we wwil get R1 simillarly foe aluminum wire = (alumiium ) =2.82*10-8 m plug values we will get R2 R = R1+ R2 gives total resistance ofwire . (b) current through wire = I = v/R = 68/R = ----A (b) current through wire = I = v/R = 68/R = ----A

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