About part d of question 55, how does the current not changewhen it went from .2

Question

About part d of question 55, how does the current not changewhen it went from .21A to .25A? With the internal resistance, thecurrent through A is less than without the internal resistance. Sowhy is there no change in hte current through A? Is it just too insignifacnt? About part d of question 55, how does the current not changewhen it went from .21A to .25A? With the internal resistance, thecurrent through A is less than without the internal resistance. Sowhy is there no change in hte current through A? Is it just too insignifacnt?

Explanation / Answer

(a)             When the switch is open then the total resistance in thecircuit

                                    6 + 0.5 = 6.5

                                   Totalresistance                      =          3 +0 .5 =3.5

                                   Current                       =     1.5/3.5                    

                       Out of this current and left shall flow through A & B each

c)              Change in Current = 0.29 – 0.21 = 0 .08 A

                                   Fractional change 0.08/0.29

(d)             If the internal resistance of the battery be zero then when theswitch is open then current A = =1.5/6= .25A

                 When switch is closed, then total resistance is above = 3

                 Current = 1.5 / 3 =0 .5 A

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.