(a) What is the magnitude of F when the crate is in this final position? 1 N (b)

Question

(a) What is the magnitude of Fwhen the crate is in this final position?
1 N

(b) During the crate's displacement, what is the total work done onit?
2 J

(c) During the crate's displacement, what is the work done by theweight of the crate?
3 kJ

(d) During the crate's displacement, what is the work done by thepull on the crate from the rope?
4 J

(e) Knowing that the crate is motionless before and after itsdisplacement, use the answers to (b), (c), and (d) to find the workyour force F does on the crate.
5 kJ

(f) Why is the work of your force not equal to the product of thehorizontal displacement and the answer to (a)?
6

Explanation / Answer

The angle is         =Sin-1( 4.00m / 11.0m) = 21.32     The tension in the rope is         T = 210kg (9.8) /Coso = 2209.19N
     
The force F = (T )Sin = 806.85 N

b) there is no change in kinetic energy the total workdone is zero. c) The work done by the gravitational force is           Wg = - m g L [ 1 - Cos] = -1549.25J
d)here the angle is 90         W = 0 e) The work done by the force is       W = -  Wg = 1549.25 J e) The work done by the force is       W = -  Wg = 1549.25 J

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