A 0.55-kg object connected to a lightspring with a force constant of 20.0 N/mosc

Question

A 0.55-kg object connected to a lightspring with a force constant of 20.0 N/moscillates on a frictionless horizontal surface. The spring iscompressed 4.0 cm and released from rest. (a) Determine the maximum speed of theobject.
cm/s

(b) Determine the speed of the object when the spring is compressed1.5 cm.
cm/s

(c) Determine the speed of the object when the spring is stretched1.5 cm.
cm/s

(d) For what value of x does the speed equal one-half themaximum speed?
cm (a) Determine the maximum speed of theobject.
cm/s

(b) Determine the speed of the object when the spring is compressed1.5 cm.
cm/s

(c) Determine the speed of the object when the spring is stretched1.5 cm.
cm/s

(d) For what value of x does the speed equal one-half themaximum speed?
cm

Explanation / Answer

Energy stored in spring when compressed, E = (1/2)KX2 =(0.5)*20*0.042 = 0.016 N-m this energy gives kinetic energy to obejet => 0.016 = (1/2)mV2 => 0.032 = 0.55*V2 => V = 0.241 m/s If object is compresed for 1.5 cm then (0.5)*20*(0.015)2 = (0.5)*0.55*V2 => V = 0.0904 m/s

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.