a. Male pattern baldness is a recessive sex-linked trait on the X chromosome. A
ID: 175019 • Letter: A
Question
a. Male pattern baldness is a recessive sex-linked trait on the X chromosome. A woman, whose father had male pattern baldness, marries a man with this trait. What is the probability that any son born will have pattern baldness? b. In humans, normal skin color (A) is dominant over albino (a), and being non-diabetic (B) is dominant over being diabetic (b). A diabetic albino man marries a normal woman whose mother was an albino and whose father was diabetic. What are the genotypes of the man and the woman? What proportion of their children would be expected to be both non-diabetic and have normal color?Explanation / Answer
Answer:
a).
XB = Normal
Xb = Baldness
Woman father is bald means the daughter is carrier.
XBXb (Woman) x (man) XbY ----------------Parents
Xb
Y
XB
XB Xb (normal female)
XB Y (normal male)
Xb
Xb Xb (bald female)
Xb Y (bald male)
50 % or ½ of sons are bald.
50 % or ½ of daughters are bald.
b). Normal woman whose mother was an albino and whose father was diabeted meas the woman is carrier for both the characters.
aabb (Diabetic albino man) x AaBb (woman)
AB
Ab
aB
ab
ab
AaBb (normal skin color, non-diabetic)
Aabb (normal skin color, diabetic)
aaBb (albino, Non-diabetic)
aabb (albino color, diabetic)
Xb
Y
XB
XB Xb (normal female)
XB Y (normal male)
Xb
Xb Xb (bald female)
Xb Y (bald male)
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