I didne know how to solve this,can any one help me? Asimple harmonic oscillator

Question

I didne know how to solve this,can any one help me? Asimple harmonic oscillator consists of a block of mass 2.00kg attached to aspring constant 100 N/m. When t=1.00s, he positionand velocity of the block are x=0.129 m and v=3.415 m/s. (a) Whatis the amplitude of the oscillations? what were the (b) positionand (c) velocity of the block at t=0 s ? I didne know how to solve this,can any one help me? Asimple harmonic oscillator consists of a block of mass 2.00kg attached to aspring constant 100 N/m. When t=1.00s, he positionand velocity of the block are x=0.129 m and v=3.415 m/s. (a) Whatis the amplitude of the oscillations? what were the (b) positionand (c) velocity of the block at t=0 s ?

Explanation / Answer

We know that spring constant        k =m2        = k /m            =100 / 2            =50            =7.071 rad / s At t = 1.00 s, we have             tan = - v / * x                     = - 3.415 / 7.071 * 0.129                     = - 3.743              = 75o a) Amplitude xm = x(1) / cos(t + )                            = 0.129 / cos(7.071*57.30 + 75o)                            = 0.129 / cos(480)                            = - 0.065 m b) At t = 0, x(0) = xm cos =- 0.0168 m c) v(0) = - xm sin   =0.444 m /s

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