A 27200 kg rocket has a rocket motor that generates 301400 Nof thrust. What is t

Question

A 27200 kg rocket has a rocket motor that generates 301400 Nof thrust.

What is the rocket’s initial upwardacceleration?
I found this to be 1.2809m/s2             

At an altitude of 4750 m the rocket’sacceleration has increased to 1.911 m/s2 What mass offuel has it burned?
How do I find this part? A 27200 kg rocket has a rocket motor that generates 301400 Nof thrust.

What is the rocket’s initial upwardacceleration?
I found this to be 1.2809m/s2             

At an altitude of 4750 m the rocket’sacceleration has increased to 1.911 m/s2 What mass offuel has it burned?
How do I find this part?

Explanation / Answer

. 1.   Assumption_1: mass of rocket at ignition= 27200 kilograms 2.   Assumption_2: air friction isnegligible 3.   Assumption_3: the altitude of 4750 metersis close enough to Earth that g is essentially equal to 9.8m/s2 4.   (27200 kg)*(9.8 m/s2) = 266560Newtons 5.   alift_off = (301400 Newtons -266560 Newtons)/(27200 kilograms) = 1.280882m/s2 . 6.   Let equal the value of the rocket's massat the point when acceleration equals 1.911m/s2 . 7.   (301400 Newtons) - ( kg)*(9.8m/s2) = ( kg)*(1.911m/s2)      ;   solvefor 8.   = (301400 Newtons) / (11.711m/s2) = 25736.5 kilograms 9.   mgas = 27200 kilograms- 25736.5 kilograms = 1463.5 kilograms of fuel hasburned 1.   Assumption_1: mass of rocket at ignition= 27200 kilograms 2.   Assumption_2: air friction isnegligible 3.   Assumption_3: the altitude of 4750 metersis close enough to Earth that g is essentially equal to 9.8m/s2 4.   (27200 kg)*(9.8 m/s2) = 266560Newtons 5.   alift_off = (301400 Newtons -266560 Newtons)/(27200 kilograms) = 1.280882m/s2 . 6.   Let equal the value of the rocket's massat the point when acceleration equals 1.911m/s2 . 7.   (301400 Newtons) - ( kg)*(9.8m/s2) = ( kg)*(1.911m/s2)      ;   solvefor 8.   = (301400 Newtons) / (11.711m/s2) = 25736.5 kilograms 9.   mgas = 27200 kilograms- 25736.5 kilograms = 1463.5 kilograms of fuel hasburned .

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