In problem 17p on chapter 5, they are asking tofind the magnitude of the contact

Question

In problem 17p on chapter 5, they are asking tofind the magnitude of the contact force between boxes 1 and 2and between boxes 2 and 3. On step 3 in solution, you added twomasses(m2 and m3) and multiplied by force 7.50. but why you didntadd mass 1 and mass 2 in stap 2? you used only mass 1 andmultiplied by force. can you please explain? Thank you In problem 17p on chapter 5, they are asking tofind the magnitude of the contact force between boxes 1 and 2and between boxes 2 and 3. On step 3 in solution, you added twomasses(m2 and m3) and multiplied by force 7.50. but why you didntadd mass 1 and mass 2 in stap 2? you used only mass 1 andmultiplied by force. can you please explain? Thank you

Explanation / Answer

The boxes accelerates together                    F = (m1 + m2 + m3 ) a or               a   = F / ( m1 + m2 + m3 )                         = 7.50 / ( 1.30 + 3.20 + 4.90  )                        = 0.7979   m/s2 (a)       The contact force F21 acclecrates box 1 is :                   F21   = m1 a                            = 1.30 * 0.7979                           = 1.40 N (b)         The contact forceF32 accelerates box 1 and 2 .                F32   = ( m1 +m2 ) a                          = ( 1.30 + 3.20 ) ( 0.7979 )                        = 3.59 N Hope this helps u!

Related Questions

Navigate

• Browse (All)
• Browse I
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.