In a friendly game of handball, you hit the ballessentially at ground level and

Question

In a friendly game of handball, you hit the ballessentially at ground level and send it toward the wall with aspeed of 14 m/s at an angle of 34 degrees above the horizontal. Howlong does it take for the ball to reach the wall if it is 3.8 maway? How high is the ball when it hits the wall? Thanks! In a friendly game of handball, you hit the ballessentially at ground level and send it toward the wall with aspeed of 14 m/s at an angle of 34 degrees above the horizontal. Howlong does it take for the ball to reach the wall if it is 3.8 maway? How high is the ball when it hits the wall? Thanks!

Explanation / Answer

         Given thatthe iniital velocity is U = 14 m/s          The angle ofinclination is = 340          Thedistance between the wall and the initial point is d = 3.8m ----------------------------------------------------------------------------     The horizontal velocity is Ux =Ucos = 14m/s*cos340 = 11.6 m/s     The verticle velocity is Uy= U sin = 14m/s* sin340 = 7.82m/s             The time taken to travell thehorizontal distance is t = horizontal distance / horizontalvelocity                                                                                   =d / Ux                                                                                   =-------- sec      The verticle distance travell bythe body is y = Uy*t + (1/2)at2                                                                         =Uy*t -(1/2)gt2                                                                                         =----------- m                  Thedistance between the wall and the initial point is d = 3.8m ----------------------------------------------------------------------------     The horizontal velocity is Ux =Ucos = 14m/s*cos340 = 11.6 m/s     The verticle velocity is Uy= U sin = 14m/s* sin340 = 7.82m/s             The time taken to travell thehorizontal distance is t = horizontal distance / horizontalvelocity                                                                                   =d / Ux                                                                                   =-------- sec      The verticle distance travell bythe body is y = Uy*t + (1/2)at2                                                                         =Uy*t -(1/2)gt2                                                                                         =----------- m                                                                                 =Uy*t -(1/2)gt2                                                                                         =----------- m        

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