(a) At a certain time during the acceleration,Jeep P has a speed of 38.0 m/s. Wh

Question

(a) At a certain time during the acceleration,Jeep P has a speed of 38.0 m/s. What is the velocity ofJeep P relative to Jeep B at that time?
m/s <---- here ithink its 18 m/s?? is this right or completely offtrack
° (counterclockwise from dueeast) <--- I'm confused here howexactly you figure this out?

(b) What is the acceleration of Jeep P relative to JeepB?
m/s2 <----how is this calculated? change in velocity over time? is thiscrazy?
° (counterclockwise from due east)<---- don't know how to calculate this buti am guessing its like a? ***I don't need to see answers, I just want to know theprocess that goes into this, answers are nice but they don't helpyou too much in the long run thanks and lifesaver promised! ***I don't need to see answers, I just want to know theprocess that goes into this, answers are nice but they don't helpyou too much in the long run thanks and lifesaver promised!

Explanation / Answer

The problem implies, but does not state, that the two jeepsstarted from the same point. Otherwise the direction of the line joining them cannot bedetermined. Let P be the distance that jeep travels and B the distancethat jeep B travels. Then P2 + B2 - 2 P B cos =d2    where d is the distance betweenthem. Where (180 - 1) + 2 + = 180    and = 1 -2 = 34 deg 2 P dP/dt + 2 B dB/dt - 2 cos (P dB/dt + B dP/dt) = 2 ddd/dt dB/dt is given and you can easily obtain dP/dt from dP =a t   and t = v / a Now you have all the information needed to solve theproblem. The sine rule can give you the needed direction of sided. Obtain d2d / dt2 by differentiating asecond time (d2B / dt2) = 0 The above just uses 3 sides of a triangle - you can find from the diagram You're given  d2P / dt2 and and dB / dt Solve for the 1st and 2nd derivatives of d then use the Law ofSines for the direction of d Hope you find this useful.

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