A farm truk moves due north with a constant velocity of 9.50 m/s on a limitless

Question

A farm truk moves due north with a constant velocity of 9.50 m/s on a limitless horizontal streach of road. A boy riding on the back of the truck throws a can of soda upward and catches the projectile at the same location on the truck bed, but 16.0 m farther down the road.(a) In the farme of reference of the truck,at what angle to the vertical does the boy throw the can? (b) What is the initial speed of the can relative to the truck? (c) what shape of can's trajectory as seen by  the boy? (d)An observer on the ground watches the boy throw the can and catch it. in this observer's ground frame of reference, describe the shap of the can's path and determine the initial velocity of the can.

Explanation / Answer

(a) in the "truck" frame of reference, the can goes straightup and straight down so the angle to the vertical is 0º (b) the velocity of the truck is 9.50 m/s, and the boy catchesthe can 16.0 m from where he threw it so the time that the can is in the air is 16.0m /9.50m/s , or 1.68s (approx) time going up is equal to time coming down, so it takesthe can 0.84s to reach peak altitude since gravitational acceleration is 9.81m/s2; theinitial velocity is 0.84 * 9.81 or 8.24m/s(approx) this is relative to the truck (c) as seen by the boy (riding on the truck) the trajectory isa straight line, up and then down (see answer (a)) (d) to a ground observer, the can follows a parabolicpath --- like an artillery projectile the initial velocity (from the ground reference) is the VECTORsum of the truck and the can in the truck reference v2 = 16.02 + 8.242 --- this is the magnitude of the velocity tan = 8.24 / 16.0 --- this is the angle ofthe velocity , relative to the horizontal (this is the complementof the vertical angle)

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