Reference: Ref 19-4 If a proton which has a charge of +1.60 ×10 – 19 C is moved

Question

Reference: Ref 19-4 If a proton which has a charge of +1.60 ×10–19 C is moved from rest atA to rest at B, what is change inelectrical potential energy of the proton? zero joules – 4.3 ×10–15 J + 2.1 ×10–14 J + 3.2 × 10–14 J Two point charges are separated by 1.00 10^-2 m. One charge is -2.8 10^-8 C; and the other is +2.8 10^-8 C. The pointsA and B are located 2.5 10^-3 m from the lower and upper pointcharges as shown. Reference: Ref 19-4 If a proton which has a charge of +1.60 10^-19 C is moved from rest atA to rest at B, what is change inelectrical potential energy of the proton? b. zero joules c. - 4.3 10^-15 J d. + 2.1 10^-14 J e. + 3.2 10^-14 J

Explanation / Answer

let Q1 and Q2 be the charges seperated by a distance d, let q be the test charge that is to be moved from intialposition P1 to final position P2 which is d1 distance from Q1and d2 distance from Q2 in order to move this charge to a new position d3 fromthe first charge and d4 from the second charge the Work that mustbe done on the test charge q is equal to the potential differencebetween the two points due to the two charges Potential energy of test charge q atinitial position P1 d ue to Q1 and Q2                            Vi = V1 +V2                                = k Q1* q / d1 + kQ2 * q / d2 potential energy of test charge q at finalposition P2 due to Q1 and Q2                         Vf = V3 +V4                             =  k Q1* q / d3 + kQ2 * q / d4 where k = 1/4 the work that must be done on the positive testcharge                      W = Vf - Vi Using the above relations we can solve for Work done ' W' using the given values.      

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