Two point charges of magnitude 7.64 nC and -3.66 nC areseparated by 39.4 cm. The

Question

Two point charges of magnitude 7.64 nC and -3.66 nC areseparated by 39.4 cm. The acceleration of gravity 9.8m/s2. The Coulomb constant is 8.98755*10^9N*m2 / C2. 1) What is the electric potential at a point midwaybetween the charges? Answer in units of V. For this quetions theanswer is 181.6 V. 2)What is the potential energy of the pair of charges?Answer in units of V. For this question i don't understand how canthe answer be in V if it is asking for potential energy. Shouldn'tthe answer be in Joules? Anyway i tried using this formula but theanswer was wrong. Work = V* q(charge). Help Please!!! Two point charges of magnitude 7.64 nC and -3.66 nC areseparated by 39.4 cm. The acceleration of gravity 9.8m/s2. The Coulomb constant is 8.98755*10^9N*m2 / C2. 1) What is the electric potential at a point midwaybetween the charges? Answer in units of V. For this quetions theanswer is 181.6 V. 2)What is the potential energy of the pair of charges?Answer in units of V. For this question i don't understand how canthe answer be in V if it is asking for potential energy. Shouldn'tthe answer be in Joules? Anyway i tried using this formula but theanswer was wrong. Work = V* q(charge). Help Please!!!

Explanation / Answer

The definition of electric potential at a point is the workdone in bringing a unit test charge from infinity to that point. The answer to part (a) must therefore be in J / C V = K [ Q1 / (D / 2) + Q2 / (D / 2)] = 2K / D * (Q1 + Q2)   where K = 1 /(4 0) The potential at either charge is then K Q/ D) where Qis the charge on the other charge. So the potential energy is V Q giving for the energy V Q = KQ1 Q2 / D (in Joules) Again, V = work / charge = J / C   and PE = J = VQ You are correct in that both answers cannot be in Valone.

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