I am having difficulty in my college physics course, I havebeen given a set of h
ID: 1752153 • Letter: I
Question
I am having difficulty in my college physics course, I havebeen given a set of homework equations I do not understand. Thefirst equation is as follows: A block with a mass of 5.00 kg is attached to horizontalspring that has a spring constant of 4.00x10^2 N/m. The surface theblock rests upon is frictionless. Suppose the spring system startsat x=0 and is then kicked to the right at an inital speed of 0.600m/s. What distance from the origin does the objecttravel beforecoming to rest, assuming the surface is frictionless. And does theanswer change is the coefficent of kinetic friction is 0.150? (usethe quadratic equation) I am having difficulty in my college physics course, I havebeen given a set of homework equations I do not understand. Thefirst equation is as follows: A block with a mass of 5.00 kg is attached to horizontalspring that has a spring constant of 4.00x10^2 N/m. The surface theblock rests upon is frictionless. Suppose the spring system startsat x=0 and is then kicked to the right at an inital speed of 0.600m/s. What distance from the origin does the objecttravel beforecoming to rest, assuming the surface is frictionless. And does theanswer change is the coefficent of kinetic friction is 0.150? (usethe quadratic equation)Explanation / Answer
The initial KE of the block is totally converted to PE whenthe block comes to rest. 1/2 m v2 = 1/2 k x2 where xis the distance the spring is compressed Then x = v (m / k) = .6 * (5 / 400) = .067 m =6.7 cm If friction is present then some of the initial KE is lost tofriction and our equation becomes 1/2 m v2 = 1/2 k x2 + m g x when we include the energy lost to friction You can solve this equation for x by using the quadraticformula and the values given.Related Questions
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