NASA plans to use a new type of orcket, a Variable SpecificImpulse Magnetoplasma
ID: 1752335 • Letter: N
Question
NASA plans to use a new type of orcket, a Variable SpecificImpulse Magnetoplasma Rocket (VASIMR), on future missions. A VASIMRcan produce 1200 N of thrust (force) when in operation. a) If a VASIMR has a mass of 2.2 x 10^5 kg, what accelerationwill it experience? Assume that the only force acting on therocket is its own thrust, and that the mass of the rocket isconstant. b) Over what distance must the rocket accelerate from rest toachieve a speed of 9700 m/s? c) When the rocket has covered one-quarter the accelerationfound in part B, is its average speed 1/2, 1/3, or 1/4 its averagespeed during the final three-quarters of the accelerationdistance? NASA plans to use a new type of orcket, a Variable SpecificImpulse Magnetoplasma Rocket (VASIMR), on future missions. A VASIMRcan produce 1200 N of thrust (force) when in operation. a) If a VASIMR has a mass of 2.2 x 10^5 kg, what accelerationwill it experience? Assume that the only force acting on therocket is its own thrust, and that the mass of the rocket isconstant. b) Over what distance must the rocket accelerate from rest toachieve a speed of 9700 m/s? c) When the rocket has covered one-quarter the accelerationfound in part B, is its average speed 1/2, 1/3, or 1/4 its averagespeed during the final three-quarters of the accelerationdistance?Explanation / Answer
a=F/m a=1200 / 2.2 x 105= 5.45 x 10-3m/s2 a= b) Over what distance must the rocket accelerate from rest toachieve a speed of 9700 m/s? since S=0.5at2 and v=at then t= V/a and S= 0.5 a ( V/a)2 S= 0.5 ( V)2/a S= 0.5 (9700)2 / 5.45 x 10-3 S=8.62 x109 m S=8.62 x109 m c) When the rocket has covered one-quarter the accelerationfound in part B, is its average speed 1/2, 1/3, or 1/4 its averagespeed during the final three-quarters of the accelerationdistance? I presume 1/4 distance 0.25S = 0.5at2 Then t= [0.5 S /a] and with ta knowledge V=at V= [0.5 S a] V= [0.5 x 8.62x109 x 5.45 x 10-3]V=4850 m/s Then I suppose 1/2 applies. Then t= [0.5 S /a] and with ta knowledge V=at V= [0.5 S a] V= [0.5 x 8.62x109 x 5.45 x 10-3]
V=4850 m/s Then I suppose 1/2 applies.
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