The problem states: After being struck by a bowling ball, a 2kg pin sliding to t

Question

The problem states: After being struck by a bowling ball, a 2kg pin sliding to the right at 4m/s collides head-on with another 2kg pin initially at rest. Find the final velocity of the second pin if (a) Thefirst pin moves to the right after the collision at .9 m/s and (b)The first pin stops moving when it hits the second pin. I am thinking that the part a is an inelastic collision? I wastrying to use m1v1i + m2v2i = (m1 + m2) vf and then solve for vfinal...is this correct? or should I be using something else sinceI need v final of the second pin? For part b, i'm not really sure what to use. I know it has todo with energy of the system and K and U but I am unsure exactlyhow to think the set up. The problem states: After being struck by a bowling ball, a 2kg pin sliding to the right at 4m/s collides head-on with another 2kg pin initially at rest. Find the final velocity of the second pin if (a) Thefirst pin moves to the right after the collision at .9 m/s and (b)The first pin stops moving when it hits the second pin. I am thinking that the part a is an inelastic collision? I wastrying to use m1v1i + m2v2i = (m1 + m2) vf and then solve for vfinal...is this correct? or should I be using something else sinceI need v final of the second pin? For part b, i'm not really sure what to use. I know it has todo with energy of the system and K and U but I am unsure exactlyhow to think the set up.

Explanation / Answer

       Given that the mass ofpin is m = 2 kg        Initial velocity ofthe pin is u1 = 4 m/s (right)        Initial velocity ofthe second pin is u2 = 0 m/s ---------------------------------------------------------------------- (a)  The first pin moves to the right afterthe collision at   v1 = .9 m/s           Fromthe conservation of momentum                  m*u1 + m*u2 = m*v1 + m*v2                       u1+ u2 - v1 = v2                                                     v2 = --------- m/s (b)The first pin stops moving when it hits the secondpin v1 = 0 m/s                       Fromthe conservation of momentum                  m*u1 + m*u2 = m*v1 + m*v2                       u1+ u2 - v1 = v2                                                     v2 = --------- m/s           Fromthe conservation of momentum                  m*u1 + m*u2 = m*v1 + m*v2                       u1+ u2 - v1 = v2                                                     v2 = --------- m/s

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