This problem resembles question 44 on chapter 5, but itsays: A block of mass 7 k
ID: 1753344 • Letter: T
Question
This problem resembles question 44 on chapter 5, but itsays: A block of mass 7 kg is pushed up against a wall by a force ofP that makes an angle of 50 degrees with the horizontal. thecoefficient of static friction between the block and the wall is.216..then it says to find the possible values for the magnitude ofP that allow the block to remain stationary. I found the minimun of P to be 75.818 N using thisformula: fs+Psin = mg, where fs=.216*Pcos Then, it asks me to find the maximum P for the object toremain stationary, and I'm not sure what the formula to figure thatout should be. This problem resembles question 44 on chapter 5, but itsays: A block of mass 7 kg is pushed up against a wall by a force ofP that makes an angle of 50 degrees with the horizontal. thecoefficient of static friction between the block and the wall is.216..then it says to find the possible values for the magnitude ofP that allow the block to remain stationary. I found the minimun of P to be 75.818 N using thisformula: fs+Psin = mg, where fs=.216*Pcos Then, it asks me to find the maximum P for the object toremain stationary, and I'm not sure what the formula to figure thatout should be.Explanation / Answer
the forces acting on the block in the x and y directionsare Fx = P1 - fs = P * cos -s* n -------------(1) and Fy = (n + (-P2)) + (-w) = 0 or n = P2 + w = P * sin + m * g -------------(2) from (1) and (2) we get Fx = P * cos - s* (P * sin+ m * g) the magnitude of P that allow the block to remain stationarycan be obtained by substituting Fx = 0 or P * cos - s* (P * sin + m * g)= 0 or P = (s* m * g/(cos -s* sin)) s= .216 m = 7 kg g = 9.8 m/s^2 and = 50oRelated Questions
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