A 10-eV electron is incident on a potential barrier of height 25 eVand width 1 n

Question

A 10-eV electron is incident on a potential barrier of height 25 eVand width 1 nm. a) use equation 6-76 to calculate the order of magnitude ofthe probability that the electron will tunnel through thebarrier. b) Repeat your calculation for a width of 0.1 nm.
equation 6-76:
T = 16*(E/V0)*(1-(E/V0))*e-2*alpha*a a a) use equation 6-76 to calculate the order of magnitude ofthe probability that the electron will tunnel through thebarrier. b) Repeat your calculation for a width of 0.1 nm.
equation 6-76:
T = 16*(E/V0)*(1-(E/V0))*e-2*alpha*a a

Explanation / Answer

T =16(E/V0)(1-(E/V0))e-2a a) E = 10 eV, V0 = 25 eV, a = width = 10-9m, = (2m(E-V0))/hbar >> youhave to compute this; answer should be m-1. T = 3.84 e-2a b) E = 10 eV, V0 = 25eV, a = width = 10-10 m, = same as in part (a). T = 3.84 e-2a hope this helps!

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