Calculate the force required to pull a copper ball of radius4.00 cm upward throu

Question

Calculate the force required to pull a copper ball of radius4.00 cm upward through a fluid at theconstant speed 6.00 cm/s. Take the dragforce to be proportional to the speed, with proportionalityconstant 0.950 kg/s. Ignore the buoyant force. I realize that the resistance force= -bV, where b is theproportionallity constant. I'm stuck on how to solve for therequired force to pull the ball out under these conditions. Pleasehelp, thank you! Calculate the force required to pull a copper ball of radius4.00 cm upward through a fluid at theconstant speed 6.00 cm/s. Take the dragforce to be proportional to the speed, with proportionalityconstant 0.950 kg/s. Ignore the buoyant force. I realize that the resistance force= -bV, where b is theproportionallity constant. I'm stuck on how to solve for therequired force to pull the ball out under these conditions. Pleasehelp, thank you!

Explanation / Answer

Since the upward velocity is constant, the resultant force onthe ball is zero . Thus the upward applied force equals the sum ofthe gravitational & drag forces both downward thus     F = mg +bv the mass of the copper ball is    m = 4r3/3         =4/3*(8.92*103kg/m3)(4*10-2m)3         = ------- tyhe applied force is then      F = mg + bv          =m(9.8m/s2)+(0.950 kg/s)(6*10-2m/s)             =---------         = ------- tyhe applied force is then      F = mg + bv          =m(9.8m/s2)+(0.950 kg/s)(6*10-2m/s)             =---------

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