So now let\'s say that you find a slope of8.002×10 -14 for square plates of widt

Question

So now let's say that you find a slope of8.002×10-14 for square plates of width 13.0 cm.What do you get for the value of the permittivity of free space?(Ignore units for now.) I have set the slope equal to oA/2, whichgives me 8.002x10-14 =o(0.13x0.13)/2 Which is about 9.5 * 10-12, but it says the answeris inccorect, any suggestions? So now let's say that you find a slope of8.002×10-14 for square plates of width 13.0 cm.What do you get for the value of the permittivity of free space?(Ignore units for now.) I have set the slope equal to oA/2, whichgives me 8.002x10-14 =o(0.13x0.13)/2 Which is about 9.5 * 10-12, but it says the answeris inccorect, any suggestions?

Explanation / Answer

The beginning portion of the question is this: Now we also know that the charge on a pair of parallel platesis proportional to the potential difference V, namely
q=CV.
We also know that the capacitance of two parallel plates is givenby
C=0A/d,
where 0=8.85×10-12 isthe permittivity of free space and d is the separationbetween the plates. Combine these equations and to get the force asa function of the potential. So now if you were to make a graph offorce (F) vs.V2/d2, the slope of thegraph would be

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