Red-green color blindness is an X-linked recessive disorder. In a population (n

Question

Red-green color blindness is an X-linked recessive disorder. In a population (n = 1000) that contains an equal number of males and females, the frequency of the normal allele, X 1, is 0.90 and the frequency of the mutant allele that causes color blindness, X 2, is 0.10. How many females in this population are carriers of the red-green colorblindness trait? Assume that the population is in Hardy-Weinberg equilibrium. The answer is 180 right,, because 2(0.90)(.10) x 1000 = 2pq x population or is it 90?

Explanation / Answer

Answer:

The frequency of color blindness allele = q = 0.1

The frequency of normal allele = p = 0.9

The frequency of females in the population are carriers of the red-green colorblindness trait= 2pq = 2 * 0.9 * 0.1 = 0.18

Number of female carriers in the population are carriers = Carrier frequency * total population

= 0.18 * 1000 = 180

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