Capacitor A and capacitor B both have the same voltage across theirplates. Howev

Question

Capacitor A and capacitor B both have the same voltage across theirplates. However, the energy of capacitor A can meltm kilograms of ice at 0 degrees C, while the energyof capacitor B can boil away water at 100 degrees C. (a)Which requires more energy, melting the ice or boiling the water? (b) Which capacitor has greater capacitance? Explainyour answers.
The capacitance of capacitor A is 9.3 X10-6 F. What is the capacitance of capacitorB? Be sure your answer is consistent with your answers to theConcept Questions.
Any explanation is greatly appreciated!
The capacitance of capacitor A is 9.3 X10-6 F. What is the capacitance of capacitorB? Be sure your answer is consistent with your answers to theConcept Questions.
Any explanation is greatly appreciated!

Explanation / Answer

Water requires 2257 kJ/kg to change from liquid to steam. (ieboil). To change from ice to liquid water it takes
333.55 kJ/kg.    It take more energy to boil waterthan to melt ice.   This means that capacitor B has thegreater capacitance. Now the work done to charge a capcitoris found by this equation. W=Q^2/2C. Q is the charge and C isthe Capcitance. This can also be rewritten as.5*C*V^2.   this is also the potencial energy thatis stored in the capacitor. So to find capcitance of B you must find the voltage. 333.55 kJ=333550 J 333550 J=.5*9.3*10^-6*V^2 V=267826 Volts 2257000=.5*C*267826^2 C=6.3*10^-5 F for B

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