A shopper in a supermarket pushes a cart with a force of 35 Ndirected at an angl

Question

A shopper in a supermarket pushes a cart with a force of 35 Ndirected at an angle of 25 degrees below the horizontal. The forceis just sufficient to overcome various frictional forces, so thecart moves at constant speed. (a) Find the work done by the shopperas she moves down a 50.0-m length aisle. (b) What is the net workdone on the cart? Why? (c) The shopper goes down the next aisle,pushing horizontally and maintaining the same speed as before. Ifthe work done by frictional force doesn't change, would theshopper's applied force be larger, smaller, or the same? What aboutthe work done on the cart by the shopper?

Explanation / Answer

F = 35 N, = 25o, constant speed. d = 50.0 m a) the work done by the shopper W = Fcos*d =1.59*103 J b) the net work done on the cart = 0, because the kinetic energyhas no change c) work done by the friction Wf = -W = -Fcos*d,the new force = F', the work W' = F'*d since the speed is the same, W' + Wf = 0, so F'*d -Fcos*d = 0, F' = Fcos, so F'

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