The problem is supposedy easy, so i think I\'m missingsomething simple - at any
ID: 1755528 • Letter: T
Question
The problem is supposedy easy, so i think I'm missingsomething simple - at any rate, I need some help. A jewler's lens of focal length 5.0cm is used as a magnifier.With the lens held near the eye, determine (a) the angular magnification when the object is at the focalpoint of the lens (b) the angular magnification when the image formed by thelens is at the near point of the eye (25cm) For part a), I've been assuming angular magnification = 1+ (25/ f), so the answer would be 1+5 = 6cm. However, I then get stuck because I don't know what thedifference is between the numbers for this part and what I shouldbe plugging in part B. The problem is supposedy easy, so i think I'm missingsomething simple - at any rate, I need some help. A jewler's lens of focal length 5.0cm is used as a magnifier.With the lens held near the eye, determine (a) the angular magnification when the object is at the focalpoint of the lens (b) the angular magnification when the image formed by thelens is at the near point of the eye (25cm) For part a), I've been assuming angular magnification = 1+ (25/ f), so the answer would be 1+5 = 6cm. However, I then get stuck because I don't know what thedifference is between the numbers for this part and what I shouldbe plugging in part B.Explanation / Answer
Given : A jewler's lens of focal length ( f ) = 5.0cm Image distance = 25 cm magnification ( m ) = 25cm / f = 25 cm / 5cm = 5 mmax = 1 + 25cm/f = 1 + 25cm / 5cm = 1 + 5 = 6 I hope it helps youRelated Questions
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