Using newtonian physics(kinetic energy = 1/2mv2), how much work [keV] isneeded t

Question

Using newtonian physics(kinetic energy = 1/2mv2), how much work [keV] isneeded to accelerate an electron from rest to 1.23c?

If we do that much work on an electron, what will its final speedactually be? Find in terms of c, to 3 significant figures. Using newtonian physics(kinetic energy = 1/2mv2), how much work [keV] isneeded to accelerate an electron from rest to 1.23c?

If we do that much work on an electron, what will its final speedactually be? Find in terms of c, to 3 significant figures. Find in terms of c, to 3 significant figures.

Explanation / Answer

From Work - Energy theorem we have :               Workdone   W   =   Change in Kineticenergy                                         = 1/ 2 m v22  -   1/ 2 m v12                                          =  1/2 * m * [ ( 1.23 c)2 - 0 ]                                         = 1/2 * 9.11 x 10-31 kg * ( 1.23 )2 * c2                                         =   6.891 x 10-31  c2          J Hope this helps u!

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