Correct, computer gets: 37.3cm 2). If you place an object very far from the mirr
ID: 1756338 • Letter: C
Question
Correct, computer gets: 37.3cm
2). If you place an object very far from the mirror, what is thelocation of the image?
Correct, computer gets: 37.3cm
3. What is the magnification of the image?
Answer:
5. What is the magnification of theimage?
6. If a diverging lens of focal length -67.0 cm is then placed27.0 cm from the first lens on the opposite side of the lens fromthe object, what is the location of the new image?
Answer:
7. What is the magnification due to thetwo-lens system?
Explanation / Answer
(4) Given : Focal length (f) = 30.0 cm object distance ( u) = 47.65 cm We know that : 1/ f = 1/ u + 1/ v or 1/ v = 1/f - 1/ u = 1/ 30 - 1/ 47.56 Imagedistance (v) = 81.25 cm (5) Magnification (M) = - v / u = - 81.25 / 47.65 = 1.705 (6) Here Object distance is : 81.25 -27.0 cm u` = 54.25 cm Focal length (f ` ) = - 67.0 cm We have : 1 / f ` = 1/ u` + 1/ v` or 1/ v` = 1/ f ` - 1 / u` = - 1 / 67.0 - 1 / 54.25 New Image location is : v` = - 29.977 cm ˜ - 30 cm (7) Magnification (M `) = - v` / u` = 30.0 / 54.25 = 0.553 Hope this helps u!Related Questions
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