For the following problem, I am having trouble understandingthe right hand rules

Question

For the following problem, I am having trouble understandingthe right hand rules. How do you determine the direction?? An electron starts moving northward in a magnetic field with avelocity of 3*106 m/s. The force is in the positivey-direction and the value is 2*10-13 N. Determine themagnitude and direction of the magnetic field. For the following problem, I am having trouble understandingthe right hand rules. How do you determine the direction?? An electron starts moving northward in a magnetic field with avelocity of 3*106 m/s. The force is in the positivey-direction and the value is 2*10-13 N. Determine themagnitude and direction of the magnetic field.

Explanation / Answer

Velocity (v) of the electron = (3*106m/s)Force (F) acting on the electron =2*10-13 N Charge (q) of the electron = 1.6*10-19C We know that the force acting on the electron due to the presenceof magnetic field is                    F = Bqv                    B = (F) / (qv)                        = (2*10-13 N) /[(1.6*10-19C)(3*106 m/s)]                        = 0.42 T

Related Questions

Navigate

• Browse (All)
• Browse F
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.