Greetings, For the question below I chose to solve for v using: mgh - W =(0.5)mv

Question

Greetings, For the question below I chose to solve for v using:mgh - W =(0.5)mv2f Is this correct? Question: "A 60.0kg skier starts from rest at the top of a skislope 65.0m high. If frictional forces do -10.5kJ of work on her asshe descends, how fast is she going at the bottom of theslope?" Thanks! Greetings, For the question below I chose to solve for v using:mgh - W =(0.5)mv2f Is this correct? Question: "A 60.0kg skier starts from rest at the top of a skislope 65.0m high. If frictional forces do -10.5kJ of work on her asshe descends, how fast is she going at the bottom of theslope?" Thanks!

Explanation / Answer

          Giventhat the mass of skier is m = 60.0 kg           Heightof incline is h = 65 m           Thework done due to friction is W = -10.5 kJ ------------------------------------------------------------------      From work energy theorem the network done                              mgh - W = (1/2)mV2 - (1/2)mU2                              mgh - W = (1/2)mV2 - 0                                       V2 = 2gh - 2W / m    slove for V = -------- m/s                                    

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