You identify a locus t has three alleles A ,A and A and you want to check to det
ID: 175687 • Letter: Y
Question
You identify a locus t has three alleles A ,A and A and you want to check to determine if they are in Hardy-Weinberg equilibrium. You determine the genotype a group of genetics students and get the following distribution. Fill in the blanks to four decimal points and use the Chi-square test to determine if they are in HWE. Expected Number of Expected Genotype Genotype Frequency ndividuals Genotype Number A A 418 A A 721 A A 963 1024 A 1734 AA 1140 A Allele Frequency A Allele Frequency A Allele Frequency How many degrees of freedom will you use? What is the critical chi-square value with an alpha of 0.05? What is the chi-squared value for these data? Is this locus in Hardy-Weinberg Equilibrium?Explanation / Answer
A1 = p
A2 = q
A3 = r
Given, A1A1 = 418 = 0.4 = 2p
p = 0.2
Given, A2A2 = 721 = 0.7 = 2q
q = 0.35
Given, A3A3 = 963 = 0.9 = 2r
r = 0.45
A1A1
418
(0.2+0.2) = 0.4
(0.2+0.2)*100 = 400
A2A2
721
(0.35+0.35) = 0.7
(0.35+0.35)*100 = 700
A3A3
963
(0.45+0.45) = 0.9
(0.45+0.45)*100 = 900
A1A2
1024
2*(0.2+0.35)=1.0
2*(0.2+0.35)*100 = 1000
A2A3
1734
2*(0.35+0.45)= 1.6
2*(0.35+0.45)*100 = 1600
A1A3
1140
2*(0.2+0.45) = 1.3
2*(0.2+0.45)*100 = 1300
A1 allele frequency = 0.2
A2 allele frequency = 0.35
A1 allele frequency = 0.45
Kindly ask remaining questions as separate post!!!
A1A1
418
(0.2+0.2) = 0.4
(0.2+0.2)*100 = 400
A2A2
721
(0.35+0.35) = 0.7
(0.35+0.35)*100 = 700
A3A3
963
(0.45+0.45) = 0.9
(0.45+0.45)*100 = 900
A1A2
1024
2*(0.2+0.35)=1.0
2*(0.2+0.35)*100 = 1000
A2A3
1734
2*(0.35+0.45)= 1.6
2*(0.35+0.45)*100 = 1600
A1A3
1140
2*(0.2+0.45) = 1.3
2*(0.2+0.45)*100 = 1300
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