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Assume 0.62 g of a substance marketed as \"Pure Energy\" isannihilated by 0.62 g

ID: 1757652 • Letter: A

Question

Assume 0.62 g of a substance marketed as "Pure Energy" isannihilated by 0.62 g of a second substance "Anti-Pure Energy." Howlong would the energy released power a city which uses 1.8E9 W ofpower? Answer in units of h. Assume 0.62 g of a substance marketed as "Pure Energy" isannihilated by 0.62 g of a second substance "Anti-Pure Energy." Howlong would the energy released power a city which uses 1.8E9 W ofpower? Answer in units of h. Assume 0.62 g of a substance marketed as "Pure Energy" isannihilated by 0.62 g of a second substance "Anti-Pure Energy." Howlong would the energy released power a city which uses 1.8E9 W ofpower? Answer in units of h.

Explanation / Answer

   Total massannihilated   m   =   0.62    +   0.62   =   1.24   g   =   1.24* 10-3   kg    Energyreleased   E   =   m* c2   =   1.24 *10-3 * (3 *108)2   =   1.116* 1014   J    Time    t   =   Energy/ power   =   1.116 * 1014/ 1.8 * 109   =   6.2 *104   s    time inhour   t   =   6.2 *104 /3600   =   17.22   h
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