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After a laser bean passes through two thin parallel slits, thefirst completely d

ID: 1758384 • Letter: A

Question

After a laser bean passes through two thin parallel slits, thefirst completely dark fringes occur at ± 15.00with the original direction of the beam, as veiwed on a screen farfrom the slits. a) What is the ratio of the distance between the slits to thewavelength of the light illuminating the slits? b) What is the smallest angle, relative to original directionof the laser beam, at which the intensity of the light is 1/10 themaximum intensity on the screen? a) What is the ratio of the distance between the slits to thewavelength of the light illuminating the slits? b) What is the smallest angle, relative to original directionof the laser beam, at which the intensity of the light is 1/10 themaximum intensity on the screen?

Explanation / Answer

a)We have: = +- 150 for distructive interference:           (m+1/2) = d sin Here m = 0 for dark fringes so:         /2 = dsin =>   d/ = 1/2sin               = 1/2sin150               = 1.93 b) the intensity given is I = I/10 => the intensity in interference patteren is:               I = I0cos2(2d/ sin) => cos2(2d/ sin) =1/10 plug d/ value and solve this eq we get = +- 5.8960               = 1.93 b) the intensity given is I = I/10 => the intensity in interference patteren is:               I = I0cos2(2d/ sin) => cos2(2d/ sin) =1/10 plug d/ value and solve this eq we get = +- 5.8960
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