A 500-microF capacitor is charged to 10V, storing 5 x 10^-3 Cof charge in the ca

Question

A 500-microF capacitor is charged to 10V, storing 5 x 10^-3 Cof charge in the capacitor. A second 500-microF capacitor isconnected in parallel with the first, and the capacitors charged inthe same manner as before. What is the resulting charge on eachcapacitor? A 500-microF capacitor is charged to 10V, storing 5 x 10^-3 Cof charge in the capacitor. A second 500-microF capacitor isconnected in parallel with the first, and the capacitors charged inthe same manner as before. What is the resulting charge on eachcapacitor?

Explanation / Answer

the two capacitors are C1 = 500 F = 500 *10-6 F and C2 = 500 F = 500 *10-6 F when the capacitors are connected in parallel then C = C1 + C2 = 500 * 10-6 +500 * 10-6 = 1000 * 10-6 F when the capacitors are connected in parallel then thepotential difference across each capacitor is same that is 10V let the charge on the two capaitors be Q1 andQ2 respectively therefore we get Q1 = C1 * V = 500 * 10-6 * 10= 5 * 10-3 C = 5 mC and Q2 = C2 * V = 500 * 10-6* 10 = 5 * 10-3 C = 5 mC

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