a) A cart that weighs 100N starts moving with a constantacceleration of 10m/s 2

Question

a) A cart that weighs 100N starts moving with a constantacceleration of 10m/s2 in the x direction. Thereare four forces acting on the cart. One of the four is aforce in the x direction w/ magnitude 2100N. Find the other threeforces. b) If, when the speed of the cart reaches 30m/s, the force inthe x direction suddenly vanishes, how long does it take the cartto reach a complete stop? a) what I have... F1= 2100N in the x direction F2= kinetic friction F3= gravitational force F4= normal force b) drawing blanks here a) A cart that weighs 100N starts moving with a constantacceleration of 10m/s2 in the x direction. Thereare four forces acting on the cart. One of the four is aforce in the x direction w/ magnitude 2100N. Find the other threeforces. b) If, when the speed of the cart reaches 30m/s, the force inthe x direction suddenly vanishes, how long does it take the cartto reach a complete stop? a) what I have... F1= 2100N in the x direction F2= kinetic friction F3= gravitational force F4= normal force b) drawing blanks here

Explanation / Answer

Net force in the y direction is zero, so... .    gravforce = 100N            normal force = 100 N . Net force in the x direction is   ma = (100/9.8) * 10 =    102 N . So     forward force in x direction = 2100N .          force of kinetic friction =   1998N   (against dir of motion). . Now... if 2100 N force disappears, then onlythe   1998 N friction force remains. .       acc = force / mass =   1998 / (100/9.8)   =    196m/s2 . time = change in velocity / acc =   30 / 196 =    0.153seconds   (answer to b) . time = change in velocity / acc =   30 / 196 =    0.153seconds   (answer to b)

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