1. the focal lenghts of some converging lenses are beingmeasured in a small room

Question

1. the focal lenghts of some converging lenses are beingmeasured in a small room. the first lens is 2.00 meters from anilluminated object and projects a clear image onto a screen 20.0 cmfrom the lens. what is the actual focal lenght of the lens?what percent error would be incurred by assuming the focal lenghtto be 20.0 cm? the second lens is 2.00 m from the illuminatedobject and projects a clear image of the object onto a screen 2.00cm from the lens. what is the actual focal lenght of the lens? whatpercent error would be incurred by assuming the focal lenght to be2.00 cm? 2. can you suggest a way for accurately measuring the focallenght of a diverging lens without using a remote object andwithout using the parallax method to locate a virtual image.? youmay assume that simple devices like converging lenses, likesources, screens, and plane mirrors are available. 1. the focal lenghts of some converging lenses are beingmeasured in a small room. the first lens is 2.00 meters from anilluminated object and projects a clear image onto a screen 20.0 cmfrom the lens. what is the actual focal lenght of the lens?what percent error would be incurred by assuming the focal lenghtto be 20.0 cm? the second lens is 2.00 m from the illuminatedobject and projects a clear image of the object onto a screen 2.00cm from the lens. what is the actual focal lenght of the lens? whatpercent error would be incurred by assuming the focal lenght to be2.00 cm? 2. can you suggest a way for accurately measuring the focallenght of a diverging lens without using a remote object andwithout using the parallax method to locate a virtual image.? youmay assume that simple devices like converging lenses, likesources, screens, and plane mirrors are available.

Explanation / Answer

In both cases, the focal length is    f = i o / ( o + i )     where all distancesare in cm. . (a)   o = 200 cm   i = 20 cm .      f = 20 * 200 / (200 +20) =  18.18 cm .    percent difference = (20 - 18.18) /18.18 =     10.0% difference . (b)   o = 200 cm      i = 2cm .        f = 2 * 200 /( 200 + 2) =     1.98cm .    percent diff   = ( 2 -1.98) / 1.98 =     1.01%

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