A uniform disk of mass 0.90 kg and radius7.0 cm is mounted in the center of a 10

Question

A uniform disk of mass 0.90 kg and radius7.0 cm is mounted in the center of a 10 cmaxle and spun at 700 rev/min. The axle isthen placed in a horizontal position with one end resting on apivot. The other end is given an initial horizontal velocity suchthat the precession is smooth with no nutation.

(a) What is the angular velocity ofprecession?
1
(b) What is the speed of the center of mass during theprecession?

(c) What are the magnitude and direction of the acceleration of thecenter of mass?

(d) What is the vertical component of the force exerted by thepivot?
5
What is the horizontal component?
6
(a) What is the angular velocity ofprecession?
1
(b) What is the speed of the center of mass during theprecession?

(c) What are the magnitude and direction of the acceleration of thecenter of mass?

(d) What is the vertical component of the force exerted by thepivot?
5
What is the horizontal component?
6

Explanation / Answer

Nooooooooo... . Sorry, but the person in the first post totally misunderstoodthe question. . You are asked in part (a) to find the angular speed ofprecession, which is NOT the same as theangular speed of the rotation of the wheel. .    angular speed of precession =  mg r / I         . where m is mass of the wheel, r is the distance from the pivot to the wheel ( 5 cm) I is the moment of inertia of the wheel (1/2 mR2 ) and   is the angular speedof the spinning (700 rpm, which is   73.30rad/sec), . Plug in the proper values and you get the answer for part(a).

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