A particle moves along the x-axis with an acceleration givenby: a(t) = 5sin(wt)

Question

A particle moves along the x-axis with an acceleration givenby:
                                              a(t) = 5sin(wt) ft/sec2   (where "w" =0.7rad/sec)
Initially (@ t = 0) the particle is 2ft away from the origin and ismoving with a speed of:
                                              v(t) = 5 ft/sec

(a) Determine the velocity and position of the particle asfunctions of time.
(b) Determine the displacement of the particle between t = 0 secand t = 4 sec.
(c) Determine the distance traveled by the particle between 0 and 4seconds.


PLEASE SHOW ANDEXPLAIN ALL STEPS!

PLEASE SHOW ANDEXPLAIN ALL STEPS!

Explanation / Answer

                      = 5 [-cos wt ] / w + C                       = ( -5 / w ) cos wt +C           -----( 1) where C = integration constant According to problem at t= 0 , speed v( t ) = 5 ft/ s substitue this condition in eq ( 1 ) we get      5 = ( -5 / 0.7 ) cosw ( 0 ) + C      1 = -( 1/ 0.7 ) + C      C = 2.428 So, velocity of the particle as a function of time is v(t ) = ( -5 / w ) cos wt + 2.428                                                                                    = -7.142 cos wt + 2.428   since w = 0.7 rad / s
Initially (@ t = 0) the particle is 2ft away from the origin and ismoving with a speed of:
                                              v(t) = 5 ft/sec

( b ) . position x (t) = integral v( t ) dt                              = -7.142[sin wt / w ] + 2.428 t + C '                             = -10.204 sin wt + 2.428 t + C '     ----(2) where C ' = integration constant At t= 0 , x = 2 substitue this condition in eq ( 2 ) we get                      2 = -10.204 sin w( 0 ) + 2.428( 0 ) + C '                     C ' = 2 So, function of position x( t ) = -10.204 sin wt + 2.428t + 2 Therefore the distance traveled by the particle between t = 0sec and t = 4 sec is X = x( 4 ) - x( 0 ) plug the values we get X = -10.204 sin [0.7 * 4 ] +2.428* 4 +2 - [ -10.204 sin(0.7*0)-2.428*0 +2]                                      = 8.2937-2                                      = 6.2937

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.