Consider four vectors ~ F1, ~ F2, ~ F3, and ~ F4, where their magnitudes are F1

Question

Consider four vectors ~ F1, ~ F2, ~ F3, and ~ F4, where their magnitudes are F1 = 48 N, F2 = 31 N, F3 = 24 N, and F4 = 50 N. Let 1 = 120?, 2 = 150?, 3 = 31?,and 4 = 55?, measured from the positive x axis with the counter-clockwise angular direction as positive. What is the magnitude of the resultant vec- tor ~F , where ~F = ~ F1 +~ F2 +~ F3 +~ F4? Answer in units of N.
i dont understand what the question is even asking.... Consider four vectors ~ F1, ~ F2, ~ F3, and ~ F4, where their magnitudes are F1 = 48 N, F2 = 31 N, F3 = 24 N, and F4 = 50 N. Let 1 = 120?, 2 = 150?, 3 = 31?,and 4 = 55?, measured from the positive x axis with the counter-clockwise angular direction as positive. What is the magnitude of the resultant vec- tor ~F , where ~F = ~ F1 +~ F2 +~ F3 +~ F4? Answer in units of N.
i dont understand what the question is even asking....

Explanation / Answer

     The net force is along x -axisis          Fx = F1cos120 + F2 cos(-150) + F3 cos31 + F4 cos(-55)     Here F1 = 48 N, F2 = 31 N, F3 = 24 N, and F4 = 50 N F2 = 31 N, F3 = 24 N, and F4 = 50 N The net force is along y -axis is       Fy =  F1 sin120 + F2sin(-150) + F3 sin31 + F4 sin(-55) The magnitude of the net force is              F = [Fx2 + Fy2] Substitute the values for F.

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