A man stands on the roof of a 10.0 -m tall building andthrows a rock with a velo

Question

A man stands on the roof of a 10.0 -m tall building andthrows a rock with a velocity of magnitude 24.0 m/s atan angle of 38.0 above the horizontal. You can ignore airresistance. Calculate the magnitude of the velocity of the rock justbefore it strikes the ground. A man stands on the roof of a 10.0 -m tall building andthrows a rock with a velocity of magnitude 24.0 m/s atan angle of 38.0 above the horizontal. You can ignore airresistance. Calculate the magnitude of the velocity of the rock justbefore it strikes the ground.

Explanation / Answer

      Given that the height of thetower is H = 10.0 m       Initial velcoity is U =24.0 m/s       The angle with horizontal is = 380   --------------------------------------------------------------- The horizontal initial and final velocity is Ux = Vx =Ucos = 24.0m/s*cos 380 The initial verticle velcity is Uy = U sin =24m/s*sin 380 From the equation of motion the verticle displacementis                       H = Uy*t - (1/2)gt2       plug in values and slove fort =------sec Then the final verticle velocity is Vy = Uy - gt                                                        =-------- m/s     Then the magnitude of final velcity isV = (Vx2+Vy2)                                                                      =--------- m/s

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