A small rod shaped protein of length 10 nm has a positive charge +1e at one end

Question

A small rod shaped protein of length 10 nm has a
positive charge +1e at one end and a negative charge -1e
at the other.
a. What is its dipole moment in Debye (1 D = 3.338 X 10-30 Cm)?
b. Sketch the electric field around this protein.
c. The protein molecule is lying along the y axis with its midpointat the
origin. What is the magnitude of the field at a point (x,y)?
d. If a Mg2+ ion is situated at x=30 nm, y=0 what force does itexperience?
What about at x=0, y=30 nm? Give magnitude and direction.

Explanation / Answer

a) We know the formula for the dipole moment is                             p = qd                                = (1e)(10nm)                                = (1.6*10-19C)(10.0*10-9m)                                = 16.0*10-28C.m                                = [(16.0*10-28) / (3.338*10-30)] D                                = 479.3 D b) Direction of the electric field is from the positive charge +1e tothe negative charge -1e.

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