(In this problem, we are going to treat the electronas a point particle, and ass
ID: 1760606 • Letter: #
Question
(In this problem, we are going to treat the electronas a point particle, and assume that the proton, which has a muchgreater mass, does not move.) An electron is in a circular orbitaround a proton. The radius of the orbit of the electron is 4.763× 10-10 m.Calculate the magnitude of the acceleration of theelectron.
Calculate the period of the electron.
Calculate the kinetic energy of the electron.
Calculate the electrical potential energy of theelectron. (Careful with the sign of the potentialenergy!)
Calculate the total energy of theelectron eV.
Calculate the electrical potential energy of theelectron. (Careful with the sign of the potentialenergy!)
Explanation / Answer
Separation (d) between electron and proton = 4.763× 10-10 m Then the magnitude of the acceleration (a) of the electron is a =(6.67*10-11N.m2/kg2)(1.67*10-27kg)/ (4.763 ×10-10 m)2 = 4.91*10-19m/s2
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