1. A 500 kg block ispulled across the floor by a rope attached to the block. The

Question

1. A 500 kg block ispulled across the floor by a rope attached to the block. Theforce on the rope pulling the block is 600 N with the rope makingan angle of 37 degrees above the horizontal. The coefficientof kinetic friction between the block and the floor is 0.05. Calculate the acceleration of the block. please show all work thank you 1. A 500 kg block ispulled across the floor by a rope attached to the block. Theforce on the rope pulling the block is 600 N with the rope makingan angle of 37 degrees above the horizontal. The coefficientof kinetic friction between the block and the floor is 0.05. Calculate the acceleration of the block. please show all work thank you

Explanation / Answer

given mass of block = m = 500kg pulling force = F = 600N angle = = 370 coefficent kinetic friction = k =0.05 apply newton seconed law in vertical andhorizontal directio N = mg - F sin37 Fcos37 - f = ma Fcos37 - k N = ma Fcos37 - k ( mg - F sin37) = ma accleration of block = a = Fcos37 - k (mg - F sin37)/m plug in values and do caliculations a =------m/s2 coefficent kinetic friction = k =0.05 apply newton seconed law in vertical andhorizontal directio N = mg - F sin37 Fcos37 - f = ma Fcos37 - k N = ma Fcos37 - k ( mg - F sin37) = ma accleration of block = a = Fcos37 - k (mg - F sin37)/m plug in values and do caliculations a =------m/s2

Related Questions

Navigate

• Browse (All)
• Browse 1
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.