While in a third floor office building, you notice a ballmoving straight upward

Question

While in a third floor office building, you notice a ballmoving straight upward just outside the window. It takes0.27 s for the ball to move up a distanceof 1.00 m from the bottom to the top ofthe window. How long does it take before the ball reappears? What is the greatest height of the ball above the top of thewindow?
While in a third floor office building, you notice a ballmoving straight upward just outside the window. It takes0.27 s for the ball to move up a distanceof 1.00 m from the bottom to the top ofthe window. How long does it take before the ball reappears? What is the greatest height of the ball above the top of thewindow?

Explanation / Answer

        Given that the timetaken to reach the top of window t = 0.27s         Distancetravelled is S = 1.00 m ----------------------------------------------------------------------------    From the equation of motion S = Ut +(1/2)at2                                                 S= Ut - (1/2)gt2             Then we get U = --------- m/s    Time does the ball reappears is T = 2U /g                                                       =--------sec    The maximumheight reached by the ball is H =U2/2g                                                                       = -------- m      

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