Given radius R=1.34 m, Q1=1.43 * 10^-6C, Q2= -Q1, and Q3=-Q1. Calculate the tota

Question

Given radius R=1.34 m, Q1=1.43 * 10^-6C, Q2= -Q1, and Q3=-Q1. Calculate the total force on Q2. Give your answer with apositive number for a force directed to the right.

Here's what I've done:

I know that Q1 and Q2 attract each other, while Q2 and Q3 repeleach other.
I've tried applying Coulomb's law for the force on Q2 by Q1. I also applied Coulomb's law to get the force on Q2 by Q3. After doing this I tried adding the two and taking themagnitude.

The answer is supposed to be -2.05 * 10^-2 N, but I can't figureout what I'm doing wrong.

Explanation / Answer

   the only equation that we use to get theforce between two charges is the coulombs law given by    the force of attraction or repulsion betweentwo charges is direcly proportional to the product of the twocharges and    inversely proportional to the square of thedistance between them    F = q1 q2 /r2

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