your teacher (2.64m tall) tosses a basketball witha velocity of 17m/s at an angl

Question

your teacher (2.64m tall) tosses a basketball witha velocity of 17m/s at an angle of 66 deg celcius into a hoop.the hoop is 3.048 m tall. part1. how long does it take the ball to reach its maximumheight? in units of s. part2. how long does it take the ball to reach the hoop?in units of s. part 3. what is the horizontal length of the shot? in units ofm.                   your teacher (2.64m tall) tosses a basketball witha velocity of 17m/s at an angle of 66 deg celcius into a hoop.the hoop is 3.048 m tall. part1. how long does it take the ball to reach its maximumheight? in units of s. part2. how long does it take the ball to reach the hoop?in units of s. part 3. what is the horizontal length of the shot? in units ofm.                  

Explanation / Answer

(1). time taken to reach maximum height t = v sin /g                                                               = 1.584 s (2). Initial velocity u = v sin = 15.53 m /s accleration a = - g = -9.8 m / s ^ 2 distance S = 3.048-2.64 = 0.408 m from the relation S = ut + ( 1/ 2) at ^ 2                0.408 = 15.53 t +[0.5 * -9.8 t ^ 2 ]                           = 15.53 t -4.9 t ^ 2             4.9 t ^ 2 -15.53 t + 0.408 = 0                t = { 15.53 ± [ 15.53 ^ 2 - 4(4.9)(0.408) ] } / 2(4.9 )                  = { 15.53 ± 15.27 } / 9.8                  = 0.0264 s     Since we take only positivevalue (3) horizontal length of the shot = v cos *t                                                = 17 cos 66 * 0.0264                                                = 0.18318 m

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