a ball is to be shot from a level ground toward a wall at adistance x the fig in

Question

a ball is to be shot from a level ground toward a wall at adistance x the fig in the text shows the y componentr vy of theballs velocity just as it would reach the wall as a function ofthat distance x what is the launch angle In the second step, how do they equate -1/2 slope of the graphthat was provided to g/Vox? I have no idea how this was done. What equation is usedto equate them, or how do you physically look at the problem toarrive at that reasoning? Also, where does x/2 = 10m/scome from? Much appreciated. a ball is to be shot from a level ground toward a wall at adistance x the fig in the text shows the y componentr vy of theballs velocity just as it would reach the wall as a function ofthat distance x what is the launch angle In the second step, how do they equate -1/2 slope of the graphthat was provided to g/Vox? I have no idea how this was done. What equation is usedto equate them, or how do you physically look at the problem toarrive at that reasoning? Also, where does x/2 = 10m/scome from? Much appreciated.

Explanation / Answer

   from the theory we have the equationthat    x - xo = (vocoso) t    so that accorrding to our problem we getthat    t = x / vox    so the equation    vy = vosino - g t leads to    vy = voy - gt        = voy- g (x / vox)    as the slope of the graph is - 0.500 we canconclude that    (g / vox) = (1 / 2)    vox = 19.6 m / s    from the y-intercept of the graph we getthat    voy = 5.00 m / s     = tan-1(voy /voy)       = ........o        

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