a test charge q between the two positive charges one3cm away with charge 2C and

Question

a test charge q between the two positive charges one3cm away with charge 2C and one 2 cm away withcharge 3C. Find the force (in newtons) on the test charge forq = -4 µC. Give a positive answer if the force is tothe right and a negative answer if the force is to theleft.
For the previous question, find the electric field (innewtons/coulomb) at the position of test charge. Again, supply apositive value if the electric field points to the right and anegative value if it points to the left.

a test charge q between the two positive charges one3cm away with charge 2C and one 2 cm away withcharge 3C. Find the force (in newtons) on the test charge forq = -4 µC. Give a positive answer if the force is tothe right and a negative answer if the force is to theleft.
For the previous question, find the electric field (innewtons/coulomb) at the position of test charge. Again, supply apositive value if the electric field points to the right and anegative value if it points to the left.

Explanation / Answer

a test charge q between the two positive charges one3cm away with charge 2C and one 2 cm away withcharge 3C. Find the force (in newtons) on the test charge forq = -4 µC. Give a positive answer if the force is tothe right and a negative answer if the force is to the left.
the force (in newtons) on the test charge for q = -4µC.
by the2c=9*109*2*10-6*4*10-6/3*3*10-4=80Ntowards left

the force (in newtons) on the test charge for q = -4µC.
by the3c=9*109*3*10-6*4*10-6/2*2*10-4=270Ntowards right
resultant force=270-80=+190N (towards right ie positive )

For the previous question, find the electric field (innewtons/coulomb) at the position of test charge. Again, supply apositive value if the electric field points to the right and anegative value if it points to the left.

the electric field at the location of the test charge
due to 2c=9*109*2*10-6/3*3*10-4=20N/C towards left


the electric field at the location of the test charge
due to 3c =9*109*3*10-6/2*2*10-4=67.5Ntowards right
resultant field =67.5-20=+47.5N/C (towards right ie positive )

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