At a certain distance from a point charge, the potential andelectric-field magni

Question

At a certain distance from a point charge, the potential andelectric-field magnitude due to that charge are 4.98 V and 12.0V/m. (Take the potential to be zero at infinity.) a) What is the distance to the point charge? b) What is the magnitude of the charge? c) Is the electric field directed toward or away from thepoint charge? At a certain distance from a point charge, the potential andelectric-field magnitude due to that charge are 4.98 V and 12.0V/m. (Take the potential to be zero at infinity.) a) What is the distance to the point charge? b) What is the magnitude of the charge? c) Is the electric field directed toward or away from thepoint charge?

Explanation / Answer

      (a) we know that, E= V / d             d= V / E = 4.98 / 12 = 0.415 m        (b)    V= ( 9 X 10^9) ( q/ d)                4.98 =  ( 9 X 10^9) ( q/ d)                   q= 0.23 nC        (c) If the charge ispositive then the direction of E = away from the charge             Ifthe charge is negative then the direction of E= towards the charge             As,the electric potential at the given point is positive, then thegiven charge is positive.             Hence,the direction of electric field is away from the given positivecharge

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