|-v^v^-|Ro | | | | |-v^v^v^v^v^v^v^-|R | | | | |___Battery______| Sorry if the d
ID: 1761989 • Letter: #
Question
|-v^v^-|Ro| |
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|-v^v^v^v^v^v^v^-|R
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|___Battery______|
Sorry if the drawing is hard to understand but the is a batteryconnected across a uniform resister Ro.
A sliding contact can move across the resistor from x=o to x=10cmat the right.(the x distance is the distance from the far left ofthe circuit to the place where the circuit from Ro meets R) Movingthe contact changes how much resistance is to the left of thecontact and how much is to the right. Find the rate a which energyis dissipated in resistor R as a function of x. Plot the functionfor battery = 50V, R = 2000 and Ro =100.
Explanation / Answer
from the given problem we can see that the partof Ro connected in paralle with R is given by R1 = Ro x / L L = 10 cm then the voltage across r will be VR = R' / Req R ' = R R1 / (R + R1) the equivalent resistance will be Req = Ro [1 - (x / L)] +R' then the power will be PR = VR2 /R = (1 / R){[( R R1) / (R + R1)] / Ro[(1 - (x / L)) + ((R R1) / (R + R1))]} R ' = R R1 / (R + R1) the equivalent resistance will be Req = Ro [1 - (x / L)] +R' then the power will be PR = VR2 /R = (1 / R){[( R R1) / (R + R1)] / Ro[(1 - (x / L)) + ((R R1) / (R + R1))]}
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