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(please have in mind that this isintroduction to physics!...not a super advanced

ID: 1762367 • Letter: #

Question

(please have in mind that this isintroduction to physics!...not a super advanced course (just so youwount complicate your self) What vertical height does the block reachabove its starting point? Express your answer using twosignificant figures. What vertical height does the block reachabove its starting point? Express your answer using twosignificant figures. What speed does it have when it slides backdown to its starting point? Express your answer using twosignificant figures. What speed does it have when it slides backdown to its starting point? Express your answer using twosignificant figures.

Explanation / Answer

Using conservation of energy we have Kf+Uf=Ki+Ui Now K=mv2/2;     U=mgh Ui=0    Vi=V0sin35=10sin35= 5.736  Uf=mgh   Vf=0 So mgh=m(5.736)2/2 h=1.679 When it slides back down the speed at the starting point willbe the initial speed on the way up or 5.736. You now have Ki=0; Ui=mgh; Ki=mV2/2;   Uf=0 Solve for V and you will get 5.736