A carton lies on a plane at an angle of 33.0 degrees to thehorizontal. The kinet

Question

A carton lies on a plane at an angle of 33.0 degrees to thehorizontal. The kinetic friction = 0.12. * What is the acceleration as the carton slides down theplane? *If the carton starts from rest 9.3 m up the plane from itsbase, what will be the carton's speed once it reaches the bottom ofthe incline? A carton lies on a plane at an angle of 33.0 degrees to thehorizontal. The kinetic friction = 0.12. * What is the acceleration as the carton slides down theplane? *If the carton starts from rest 9.3 m up the plane from itsbase, what will be the carton's speed once it reaches the bottom ofthe incline?

Explanation / Answer

From freebody diagram we can write      mgsin - fk = ma      mgsin - kmgcos = ma a = g(sin - k cos )          = 9.8* (sin33 -0.12*cos33)          = 4.35 m/s2 Velocity at the bottom of the plane             v = 2g(sin - k cos )*l where sin33 = 9.3 / l           l =9.3 / sin33                 = 17.09 m       v = 2*4.35*17.09              = 12.19 m/s

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.